F₂ segregation will show
(a) higher number of the recombinant types
(b) segregation in the expected 9 : 3 : 3 : 1 ratio
(c) segregation in 3 : 1 ratio
(d) higher number of the parental types
[CBSE AIPMT 2007]
CONNECTING MINDS
To see this working, head to your live site.
Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridised,
Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridised,
1 answer0 replies
0
1 Comment
Share Your ThoughtsSign up to leave a comment.
Correct Option (d) Reason : Higher number of the parental types formed when RRYY and rryy genotypes are hybridised giving the condition that R and Y genes are closely
linked. Law of independent assortment does not applicable when the gene of different character occupy the same homologous chromosome i.e. are linked gene.